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Old April 5th, 2008, 08:38 PM
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Default Logic Puzzle #3

You're driving a car on 1-mile-long oval track. You drive the first lap (1 mile) at 30 mph.

At what speed would you need to drive the second lap to average 60 mph for both laps?

Dean
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Old April 5th, 2008, 08:59 PM
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I'm not that left-brained but look forward to reading the answer...
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Old April 5th, 2008, 10:09 PM
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90 mph

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Old April 5th, 2008, 10:23 PM
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The speed needed is impossible to achieve.
To average 60 mph for 2 laps, you would have to average 1 mile per minute for 2 minutes.
The first 1 mile lap at 30 mph (1/2 lap per minute) took all of the 2 minutes.
Therefore, the second lap would have to be completed instantaneously, with no time used, in order to average the two laps at 60 mph.
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Old April 6th, 2008, 02:21 AM
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Mean Dean..must be raining alot in Oregon which gives you alot of time on your hands heh....::
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Old April 6th, 2008, 03:46 AM
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Venice,

You know, I'm getting too old for this kind of thing. After all, I'm almost 90...........

But did I forget to mention that Portland State University made it into the tournament this year?!

And you know, the grass is aways greener on the rainy side of the fence.........

And you're right, I am picking on you a little my friend. But your son is a test pilot for the United States Air Force, so I guess you've kicked my a$$!

And you know, someday I'll visit NOLA again -- and the beers are on you!

Dean
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Old April 6th, 2008, 04:07 AM
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Sam,

You are quite correct!

Velocity is defined as distance over time.

If you're going to average 60 mph for 2 miles, then 2 miles, at 60 mph would take 2 minutes time. But if you're traveling at 30 mph, it would take 2 minutes to travel just the 1 mile. There would be zero time left over to travel the 2nd mile.

Therefore, if you travel along the oval track at 30 mph for the first mile, it simply isn't possible to average 60 mph for both miles. Not in this universe, anyway!

Dean
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Old April 6th, 2008, 02:09 PM
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Quote:
Originally Posted by venice
Mean Dean..must be raining alot in Oregon which gives you alot of time on your hands heh....::
Dunno about you, Dean, but I'm getting REALLY impatient for warm, sunny weather...
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Old April 7th, 2008, 05:15 PM
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But Dean, you didn't give a time limit in the original question. Therefore, it is possible to acheive the needed speed on the second lap in a race car.
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Old April 7th, 2008, 07:58 PM
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Default Re: Logic Puzzle #3

Mean Dean,

Quote:
Originally Posted by You
You're driving a car on 1-mile-long oval track. You drive the first lap (1 mile) at 30 mph.

At what speed would you need to drive the second lap to average 60 mph for both laps?
Infinity.

Time Required: (2 laps) x (1 mile/lap) / (60 miles/hur) x (60 minutes/hour) = 2 minutes

Time Expended: (1 lap) x (1 mile/lap) / (30 miles/hour) x (60 minutes/hour) = 2 minutes

Time Available = Time Required - Time Expended = 2 Minutes - 2 Minutes = 0

Limit as t->0 (1 lap) x (1 mile/lap) / (s x t) = Infinity, QED.

Norm.
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Old April 7th, 2008, 08:02 PM
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mehawk,

Quote:
Originally Posted by You
But Dean, you didn't give a time limit in the original question. Therefore, it is possible to acheive the needed speed on the second lap in a race car.
The "time limit" is implicit in the fact that you need to average a certain speed over a fixed distance. Quite simply,

distance = average spped x time

or

time = distance / average speed

as calculated in my response to the OP.

Norm.
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